Posted by admin | Posted in Cookbooks for Bar B Cues | Posted on 30-07-2009
Tags: design, more, more than a feeling, more than a feeling lyrics, more than a game, more than words, more than words lyrics, social, than, web2.0
What happens if the system thermodynamics influence their surroundings more than the other way around?
I understand that ice and water on the idea glass, where the environment and in the glass must eventually reach an equilibrium. The energy of the system (the glass) obtained is higher than the surrounding quarter (for example) loses. Who Gaines more power if the glass is hot and the cold surrounding? Does this mean that the value of the entropy of the glass hot is higher to begin with the room?! So we will lose less than they gain around here? At some point, the glass loses its heat and eventually freeze, if the surrounding temperature, so that what happens to the extent eachange entropy and heat, which networks more and who loses? Is it therefore always possible that the system itself brings its surroundings at their own level of energy without gaining or losing anything?
The crystal ice + water + Is a system, and "surroundings" are another way. When we use this term usually implies that the amount of energy in the "environment" is so great that it will not be significantly changed by an energy transfer from / to the smallest in the system. That does not mean there is no change it all: – Because energy is conserved, a reduction in energy is compensated by an increase in the energy of the other. – Any exchange of Heat will make a difference in the entropy of the two systems. So now if you want to have two systems that are of similar size, but trapped together in a box isolate them from the rest of the world, you can still do the analysis that way. To answer your questions: a) "Who gains Whatever ..?": heat is lost through the glass is gained by the surroundings. The loss is due to that heat flows from hot to colder temperatures. This does not mean that the total entropy comparison in this way: The way it works is that: 1 / T = D (entropy) / dQ, where dQ = heat, or D (entropy) = dQ / T Notice that the bottom T, the entropy changes for a faster heat transfer. So when the hot system gives a little heat, reducing the entropy is not as large as the increase in entropy gained by the cooling system. It is not the absolute amount that each system has to be is the question: is the issue that will change its entropy for heat exchange. The heat always flows from higher temperature to lower temperature, and hence heat transfer always results in increased entropy net. (I'm talking about the transfer of heat, without work being performed, which complicates matters.) B) "At some point …": At some point, the two systems will reach the same temperature. All points to obtain the same: loss of heat by a system will equal the heat gained by the other, and the loss of entropy hottest system will be more than offset by increased entropy of the system cooler. Net entropy always increases. C) Is it possible, therefore every time …": No, it is not.
Roxy Music – More than this
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